The elastic potential energy stored in a steel wire of length 20 m stretched through 2 cm is 80 J. The cross sectional area of the wire is_____mm 2 . (Given, Y = 2.0 x 10 11 N m -2 )
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The formula to calculate the Young's modulus of the material is given by
…
The formula to calculate the potential energy (U) stored into the wire is given by
U= 
x stress x strain x volume
= 
x stress x 
x A x L
= 
x stress x A x 
...
From equation and equation , it can be written that
...
Substitute the values of the known parameters into equation and solve to calculate the required cross-sectional area of the wire
= 40 mm 2
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